Base | Representation |
---|---|
bin | 111101111111111000… |
… | …1100100101000000011 |
3 | 110201122202210010201222 |
4 | 1323333301210220003 |
5 | 4140132343012120 |
6 | 141055212345255 |
7 | 12422224030106 |
oct | 1737761445003 |
9 | 421582703658 |
10 | 133140204035 |
11 | 515121a0983 |
12 | 2197847522b |
13 | c72a638227 |
14 | 663056a73d |
15 | 36e389e525 |
hex | 1effc64a03 |
133140204035 has 16 divisors (see below), whose sum is σ = 159996930912. Its totient is φ = 106359801600.
The previous prime is 133140204023. The next prime is 133140204037. The reversal of 133140204035 is 530402041331.
It is not a de Polignac number, because 133140204035 - 210 = 133140203011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133140203995 and 133140204013.
It is not an unprimeable number, because it can be changed into a prime (133140204037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18547367 + ... + 18554543.
It is an arithmetic number, because the mean of its divisors is an integer number (9999808182).
Almost surely, 2133140204035 is an apocalyptic number.
133140204035 is a deficient number, since it is larger than the sum of its proper divisors (26856726877).
133140204035 is an equidigital number, since it uses as much as digits as its factorization.
133140204035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11974.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 133140204035 its reverse (530402041331), we get a palindrome (663542245366).
The spelling of 133140204035 in words is "one hundred thirty-three billion, one hundred forty million, two hundred four thousand, thirty-five".
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