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1331402301043 = 9230511442393
BaseRepresentation
bin10011010111111101110…
…000101101111001110011
311201021120201022121222221
4103113331300231321303
5133303202442113133
62455345431541511
7165122250555433
oct23277560557163
94637521277887
101331402301043
1147370a986801
1219604bb2a897
1398720b65469
1448623d442c3
1524975beaa2d
hex135fdc2de73

1331402301043 has 4 divisors (see below), whose sum is σ = 1331404666488. Its totient is φ = 1331399935600.

The previous prime is 1331402301029. The next prime is 1331402301059. The reversal of 1331402301043 is 3401032041331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1331402301043 - 25 = 1331402301011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331402300999 and 1331402301017.

It is not an unprimeable number, because it can be changed into a prime (1331402301343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201855 + ... + 1644247.

It is an arithmetic number, because the mean of its divisors is an integer number (332851166622).

Almost surely, 21331402301043 is an apocalyptic number.

1331402301043 is a deficient number, since it is larger than the sum of its proper divisors (2365445).

1331402301043 is an equidigital number, since it uses as much as digits as its factorization.

1331402301043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2365444.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1331402301043 its reverse (3401032041331), we get a palindrome (4732434342374).

The spelling of 1331402301043 in words is "one trillion, three hundred thirty-one billion, four hundred two million, three hundred one thousand, forty-three".

Divisors: 1 923051 1442393 1331402301043