133140254131 has 4 divisors (see below), whose sum is σ = 133141236592. Its totient is φ = 133139271672.

The previous prime is 133140254129. The next prime is 133140254153. The reversal of 133140254131 is 131452041331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 133140254131 - 2¹ = 133140254129 is a prime.

It is a super-2 number, since 2×133140254131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133140254131.

It is not an unprimeable number, because it can be changed into a prime (133140254171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247716 + ... + 572401.

It is an arithmetic number, because the mean of its divisors is an integer number (33285309148).

Almost surely, 2^133140254131 is an apocalyptic number.

133140254131 is a deficient number, since it is larger than the sum of its proper divisors (982461).

133140254131 is an equidigital number, since it uses as much as digits as its factorization.

133140254131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 982460.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 133140254131 its reverse (131452041331), we get a palindrome (264592295462).

The spelling of 133140254131 in words is "one hundred thirty-three billion, one hundred forty million, two hundred fifty-four thousand, one hundred thirty-one".