133140403203 has 4 divisors (see below), whose sum is σ = 177520537608. Its totient is φ = 88760268800.

The previous prime is 133140403181. The next prime is 133140403211. The reversal of 133140403203 is 302304041331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133140403203 - 2⁵ = 133140403171 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133140403213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22190067198 + ... + 22190067203.

It is an arithmetic number, because the mean of its divisors is an integer number (44380134402).

Almost surely, 2^133140403203 is an apocalyptic number.

133140403203 is a deficient number, since it is larger than the sum of its proper divisors (44380134405).

133140403203 is an equidigital number, since it uses as much as digits as its factorization.

133140403203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44380134404.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 133140403203 its reverse (302304041331), we get a palindrome (435444444534).

The spelling of 133140403203 in words is "one hundred thirty-three billion, one hundred forty million, four hundred three thousand, two hundred three".