1331431300041 has 4 divisors (see below), whose sum is σ = 1775241733392. Its totient is φ = 887620866692.

The previous prime is 1331431300033. The next prime is 1331431300151. The reversal of 1331431300041 is 1400031341331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331431300041 - 2³ = 1331431300033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1331431299984 and 1331431300020.

It is not an unprimeable number, because it can be changed into a prime (1331431300021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221905216671 + ... + 221905216676.

It is an arithmetic number, because the mean of its divisors is an integer number (443810433348).

Almost surely, 2^{1331431300041} is an apocalyptic number.

It is an amenable number.

1331431300041 is a deficient number, since it is larger than the sum of its proper divisors (443810433351).

1331431300041 is an equidigital number, since it uses as much as digits as its factorization.

1331431300041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443810433350.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 1331431300041 its reverse (1400031341331), we get a palindrome (2731462641372).

The spelling of 1331431300041 in words is "one trillion, three hundred thirty-one billion, four hundred thirty-one million, three hundred thousand, forty-one".