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13314424537 is a prime number
BaseRepresentation
bin11000110011001100…
…11111111011011001
31021100220102211211201
430121212133323121
5204231443041122
610041102154201
7650641512151
oct143146377331
937326384751
1013314424537
115712711247
1226b6b82961
13134258021b
14904415761
1552dd5ea27
hex31999fed9

13314424537 has 2 divisors, whose sum is σ = 13314424538. Its totient is φ = 13314424536.

The previous prime is 13314424493. The next prime is 13314424579. The reversal of 13314424537 is 73542441331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11545717401 + 1768707136 = 107451^2 + 42056^2 .

It is a cyclic number.

It is not a de Polignac number, because 13314424537 - 211 = 13314422489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13314424496 and 13314424505.

It is not a weakly prime, because it can be changed into another prime (13314424037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657212268 + 6657212269.

It is an arithmetic number, because the mean of its divisors is an integer number (6657212269).

Almost surely, 213314424537 is an apocalyptic number.

It is an amenable number.

13314424537 is a deficient number, since it is larger than the sum of its proper divisors (1).

13314424537 is an equidigital number, since it uses as much as digits as its factorization.

13314424537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 37.

Adding to 13314424537 its reverse (73542441331), we get a palindrome (86856865868).

The spelling of 13314424537 in words is "thirteen billion, three hundred fourteen million, four hundred twenty-four thousand, five hundred thirty-seven".