133153400001 has 4 divisors (see below), whose sum is σ = 177537866672. Its totient is φ = 88768933332.

The previous prime is 133153399991. The next prime is 133153400011. The reversal of 133153400001 is 100004351331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100004351331 = 3 ⋅33334783777.

It is an interprime number because it is at equal distance from previous prime (133153399991) and next prime (133153400011).

It is not a de Polignac number, because 133153400001 - 2⁵ = 133153399969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133153400011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22192233331 + ... + 22192233336.

It is an arithmetic number, because the mean of its divisors is an integer number (44384466668).

Almost surely, 2^133153400001 is an apocalyptic number.

It is an amenable number.

133153400001 is a deficient number, since it is larger than the sum of its proper divisors (44384466671).

133153400001 is an equidigital number, since it uses as much as digits as its factorization.

133153400001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44384466670.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 133153400001 its reverse (100004351331), we get a palindrome (233157751332).

The spelling of 133153400001 in words is "one hundred thirty-three billion, one hundred fifty-three million, four hundred thousand, one".