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133164612053321 is a prime number
BaseRepresentation
bin11110010001110011001101…
…011001011110100101001001
3122110111102010202220021222112
4132101303031121132211021
5114423232111141201241
61151114551145032105
740022553140265422
oct3621631531364511
9573442122807875
10133164612053321
1139480881a00a82
1212b2823b185635
13593c4a49cc324
1424c52b7322649
15105ddb55ee1eb
hex791ccd65e949

133164612053321 has 2 divisors, whose sum is σ = 133164612053322. Its totient is φ = 133164612053320.

The previous prime is 133164612053287. The next prime is 133164612053381. The reversal of 133164612053321 is 123350216461331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102742327443721 + 30422284609600 = 10136189^2 + 5515640^2 .

It is an emirp because it is prime and its reverse (123350216461331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133164612053321 is a prime.

It is a super-2 number, since 2×1331646120533212 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133164612053381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66582306026660 + 66582306026661.

It is an arithmetic number, because the mean of its divisors is an integer number (66582306026661).

Almost surely, 2133164612053321 is an apocalyptic number.

It is an amenable number.

133164612053321 is a deficient number, since it is larger than the sum of its proper divisors (1).

133164612053321 is an equidigital number, since it uses as much as digits as its factorization.

133164612053321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 133164612053321 in words is "one hundred thirty-three trillion, one hundred sixty-four billion, six hundred twelve million, fifty-three thousand, three hundred twenty-one".