Base | Representation |
---|---|
bin | 111110000001011001… |
… | …1000011111011100011 |
3 | 110201210022020002021011 |
4 | 1330002303003323203 |
5 | 4140233334113201 |
6 | 141104223441351 |
7 | 12423411122521 |
oct | 1740263037343 |
9 | 421708202234 |
10 | 133190926051 |
11 | 515388950a7 |
12 | 21991456257 |
13 | c737cb7161 |
14 | 66371b1311 |
15 | 36e806d151 |
hex | 1f02cc3ee3 |
133190926051 has 4 divisors (see below), whose sum is σ = 134687453400. Its totient is φ = 131694398704.
The previous prime is 133190926027. The next prime is 133190926091. The reversal of 133190926051 is 150629091331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133190926051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133190925995 and 133190926013.
It is not an unprimeable number, because it can be changed into a prime (133190926091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 748263541 + ... + 748263718.
It is an arithmetic number, because the mean of its divisors is an integer number (33671863350).
Almost surely, 2133190926051 is an apocalyptic number.
133190926051 is a deficient number, since it is larger than the sum of its proper divisors (1496527349).
133190926051 is an equidigital number, since it uses as much as digits as its factorization.
133190926051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1496527348.
The product of its (nonzero) digits is 43740, while the sum is 40.
The spelling of 133190926051 in words is "one hundred thirty-three billion, one hundred ninety million, nine hundred twenty-six thousand, fifty-one".
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