Base | Representation |
---|---|
bin | 11110010010010101000111… |
… | …101011010110111100100011 |
3 | 122110121220010100002020112202 |
4 | 132102111013223112330203 |
5 | 114424331143431034423 |
6 | 1151143412204243415 |
7 | 40025312346623615 |
oct | 3622250753267443 |
9 | 573556110066482 |
10 | 133201023299363 |
11 | 39495267122058 |
12 | 12b3330124056b |
13 | 5942a5840b526 |
14 | 24c6d6d02adb5 |
15 | 105ece6ee6728 |
hex | 792547ad6f23 |
133201023299363 has 2 divisors, whose sum is σ = 133201023299364. Its totient is φ = 133201023299362.
The previous prime is 133201023299329. The next prime is 133201023299389. The reversal of 133201023299363 is 363992320102331.
It is a strong prime.
It is an emirp because it is prime and its reverse (363992320102331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133201023299363 - 232 = 133196728332067 is a prime.
It is not a weakly prime, because it can be changed into another prime (133201023299263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66600511649681 + 66600511649682.
It is an arithmetic number, because the mean of its divisors is an integer number (66600511649682).
Almost surely, 2133201023299363 is an apocalyptic number.
133201023299363 is a deficient number, since it is larger than the sum of its proper divisors (1).
133201023299363 is an equidigital number, since it uses as much as digits as its factorization.
133201023299363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 944784, while the sum is 47.
The spelling of 133201023299363 in words is "one hundred thirty-three trillion, two hundred one billion, twenty-three million, two hundred ninety-nine thousand, three hundred sixty-three".
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