Base | Representation |
---|---|
bin | 1100000111010101010110… |
… | …1011011000110010010011 |
3 | 1202011101120211111102121221 |
4 | 3001311111223120302103 |
5 | 3221214112020200341 |
6 | 44155103403225511 |
7 | 2543230156366144 |
oct | 301652553306223 |
9 | 52141524442557 |
10 | 13320131021971 |
11 | 4276043785834 |
12 | 15b1644b18297 |
13 | 758110377637 |
14 | 3409aa9d7acb |
15 | 181749342ed1 |
hex | c1d55ad8c93 |
13320131021971 has 2 divisors, whose sum is σ = 13320131021972. Its totient is φ = 13320131021970.
The previous prime is 13320131021933. The next prime is 13320131022047. The reversal of 13320131021971 is 17912013102331.
13320131021971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (17912013102331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13320131021971 - 239 = 12770375208083 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320131051971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660065510985 + 6660065510986.
It is an arithmetic number, because the mean of its divisors is an integer number (6660065510986).
Almost surely, 213320131021971 is an apocalyptic number.
13320131021971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320131021971 is an equidigital number, since it uses as much as digits as its factorization.
13320131021971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 34.
The spelling of 13320131021971 in words is "thirteen trillion, three hundred twenty billion, one hundred thirty-one million, twenty-one thousand, nine hundred seventy-one".
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