Base | Representation |
---|---|
bin | 1100000111010101101001… |
… | …1010001101000001010011 |
3 | 1202011101210100212102111021 |
4 | 3001311122122031001103 |
5 | 3221214242330402121 |
6 | 44155115320500311 |
7 | 2543232142205002 |
oct | 301653232150123 |
9 | 52141710772437 |
10 | 13320210403411 |
11 | 427608457422a |
12 | 15b166761a697 |
13 | 75812394c2c2 |
14 | 3409b737cc39 |
15 | 1817512c3641 |
hex | c1d5a68d053 |
13320210403411 has 24 divisors (see below), whose sum is σ = 14300091749664. Its totient is φ = 12398994368640.
The previous prime is 13320210403387. The next prime is 13320210403427. The reversal of 13320210403411 is 11430401202331.
It is not a de Polignac number, because 13320210403411 - 221 = 13320208306259 is a prime.
It is a super-2 number, since 2×133202104034112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13320210403441) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7837050 + ... + 9384016.
It is an arithmetic number, because the mean of its divisors is an integer number (595837156236).
Almost surely, 213320210403411 is an apocalyptic number.
13320210403411 is a deficient number, since it is larger than the sum of its proper divisors (979881346253).
13320210403411 is a wasteful number, since it uses less digits than its factorization.
13320210403411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1547451 (or 1547428 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13320210403411 its reverse (11430401202331), we get a palindrome (24750611605742).
The spelling of 13320210403411 in words is "thirteen trillion, three hundred twenty billion, two hundred ten million, four hundred three thousand, four hundred eleven".
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