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133202224004153 is a prime number
BaseRepresentation
bin11110010010010110001111…
…001111101011110000111001
3122110122000020000102100212112
4132102112033033223300321
5114424341123321113103
61151144131255422105
740025354166505643
oct3622261717536071
9573560200370775
10133202224004153
113949582296a367
1212b33597384935
135942bba0bb735
1424c70446a1893
15105ed67620cd8
hex79258f3ebc39

133202224004153 has 2 divisors, whose sum is σ = 133202224004154. Its totient is φ = 133202224004152.

The previous prime is 133202224004011. The next prime is 133202224004159. The reversal of 133202224004153 is 351400422202331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125296971993769 + 7905252010384 = 11193613^2 + 2811628^2 .

It is a cyclic number.

It is not a de Polignac number, because 133202224004153 - 220 = 133202222955577 is a prime.

It is a super-2 number, since 2×1332022240041532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133202224004159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601112002076 + 66601112002077.

It is an arithmetic number, because the mean of its divisors is an integer number (66601112002077).

Almost surely, 2133202224004153 is an apocalyptic number.

It is an amenable number.

133202224004153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133202224004153 is an equidigital number, since it uses as much as digits as its factorization.

133202224004153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 133202224004153 its reverse (351400422202331), we get a palindrome (484602646206484).

The spelling of 133202224004153 in words is "one hundred thirty-three trillion, two hundred two billion, two hundred twenty-four million, four thousand, one hundred fifty-three".