13320232100011 has 4 divisors (see below), whose sum is σ = 14021296947400. Its totient is φ = 12619167252624.

The previous prime is 13320232099991. The next prime is 13320232100023. The reversal of 13320232100011 is 11000123202331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13320232100011 - 2¹³ = 13320232091819 is a prime.

It is a super-4 number, since 4×13320232100011⁴ (a number of 54 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 701064847369 = 13320232100011 / (1 + 3 + 3 + 2 + 0 + 2 + 3 + 2 + 1 + 0 + 0 + 0 + 1 + 1).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13320232100111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350532423666 + ... + 350532423703.

It is an arithmetic number, because the mean of its divisors is an integer number (3505324236850).

Almost surely, 2^{13320232100011} is an apocalyptic number.

13320232100011 is a deficient number, since it is larger than the sum of its proper divisors (701064847389).

13320232100011 is an equidigital number, since it uses as much as digits as its factorization.

13320232100011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 701064847388.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13320232100011 its reverse (11000123202331), we get a palindrome (24320355302342).

The spelling of 13320232100011 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-two million, one hundred thousand, eleven".