13320233210041 has 2 divisors, whose sum is σ = 13320233210042. Its totient is φ = 13320233210040.

The previous prime is 13320233210023. The next prime is 13320233210057. The reversal of 13320233210041 is 14001233202331.

13320233210041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7664260033600 + 5655973176441 = 2768440^2 + 2378229^2 .

It is a cyclic number.

It is not a de Polignac number, because 13320233210041 - 2⁹ = 13320233209529 is a prime.

It is a super-2 number, since 2×13320233210041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13320233209988 and 13320233210015.

It is not a weakly prime, because it can be changed into another prime (13320233211041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116605020 + 6660116605021.

It is an arithmetic number, because the mean of its divisors is an integer number (6660116605021).

Almost surely, 2^{13320233210041} is an apocalyptic number.

It is an amenable number.

13320233210041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320233210041 is an equidigital number, since it uses as much as digits as its factorization.

13320233210041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13320233210041 its reverse (14001233202331), we get a palindrome (27321466412372).

The spelling of 13320233210041 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-three million, two hundred ten thousand, forty-one".