Base | Representation |
---|---|
bin | 1100000111010101110001… |
… | …1010110010111111111011 |
3 | 1202011101212201022001220111 |
4 | 3001311130122302333323 |
5 | 3221214324443112103 |
6 | 44155122523205151 |
7 | 2543233031554603 |
oct | 301653432627773 |
9 | 52141781261814 |
10 | 13320244113403 |
11 | 42760a15a9027 |
12 | 15b16769767b7 |
13 | 75812a922b46 |
14 | 3409bba35c03 |
15 | 18175423186d |
hex | c1d5c6b2ffb |
13320244113403 has 2 divisors, whose sum is σ = 13320244113404. Its totient is φ = 13320244113402.
The previous prime is 13320244113391. The next prime is 13320244113413. The reversal of 13320244113403 is 30431144202331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13320244113403 - 213 = 13320244105211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320244113413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660122056701 + 6660122056702.
It is an arithmetic number, because the mean of its divisors is an integer number (6660122056702).
Almost surely, 213320244113403 is an apocalyptic number.
13320244113403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320244113403 is an equidigital number, since it uses as much as digits as its factorization.
13320244113403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13320244113403 its reverse (30431144202331), we get a palindrome (43751388315734).
The spelling of 13320244113403 in words is "thirteen trillion, three hundred twenty billion, two hundred forty-four million, one hundred thirteen thousand, four hundred three".
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