Base | Representation |
---|---|
bin | 1100000111010101111111… |
… | …0100010001011010000011 |
3 | 1202011102000200120110122120 |
4 | 3001311133310101122003 |
5 | 3221214434041420303 |
6 | 44155132321135323 |
7 | 2543234323256124 |
oct | 301653764213203 |
9 | 52142020513576 |
10 | 13320301123203 |
11 | 42761207a7368 |
12 | 15b1691a8a543 |
13 | 758139693a59 |
14 | 3409c543604b |
15 | 181759243553 |
hex | c1d5fd11683 |
13320301123203 has 8 divisors (see below), whose sum is σ = 17763937333248. Its totient is φ = 8878432830984.
The previous prime is 13320301123193. The next prime is 13320301123219. The reversal of 13320301123203 is 30232110302331.
13320301123203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13320301123203 - 221 = 13320299026051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13320301123253) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 441961875 + ... + 441992012.
It is an arithmetic number, because the mean of its divisors is an integer number (2220492166656).
Almost surely, 213320301123203 is an apocalyptic number.
13320301123203 is a deficient number, since it is larger than the sum of its proper divisors (4443636210045).
13320301123203 is an equidigital number, since it uses as much as digits as its factorization.
13320301123203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 883958913.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 13320301123203 its reverse (30232110302331), we get a palindrome (43552411425534).
The spelling of 13320301123203 in words is "thirteen trillion, three hundred twenty billion, three hundred one million, one hundred twenty-three thousand, two hundred three".
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