1332033320041 has 4 divisors (see below), whose sum is σ = 1332112057684. Its totient is φ = 1331954582400.

The previous prime is 1332033320039. The next prime is 1332033320089. The reversal of 1332033320041 is 1400233302331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1199070990441 + 132962329600 = 1095021^2 + 364640^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332033320041 - 2¹ = 1332033320039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1332033319988 and 1332033320015.

It is not an unprimeable number, because it can be changed into a prime (1332033320141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39343440 + ... + 39377281.

It is an arithmetic number, because the mean of its divisors is an integer number (333028014421).

Almost surely, 2^{1332033320041} is an apocalyptic number.

It is an amenable number.

1332033320041 is a deficient number, since it is larger than the sum of its proper divisors (78737643).

1332033320041 is an equidigital number, since it uses as much as digits as its factorization.

1332033320041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78737642.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 1332033320041 its reverse (1400233302331), we get a palindrome (2732266622372).

The spelling of 1332033320041 in words is "one trillion, three hundred thirty-two billion, thirty-three million, three hundred twenty thousand, forty-one".