Base | Representation |
---|---|
bin | 111110000001110010… |
… | …1110000000101100010 |
3 | 110201211020020012001122 |
4 | 1330003211300011202 |
5 | 4140300234322424 |
6 | 141105420332242 |
7 | 12423632065316 |
oct | 1740345600542 |
9 | 421736205048 |
10 | 133204214114 |
11 | 51545340674 |
12 | 219959a4082 |
13 | c73a98a50a |
14 | 6638c6db46 |
15 | 36e92e545e |
hex | 1f03970162 |
133204214114 has 4 divisors (see below), whose sum is σ = 199806321174. Its totient is φ = 66602107056.
The previous prime is 133204214093. The next prime is 133204214131. The reversal of 133204214114 is 411412402331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 128870230225 + 4333983889 = 358985^2 + 65833^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33301053527 + ... + 33301053530.
Almost surely, 2133204214114 is an apocalyptic number.
133204214114 is a deficient number, since it is larger than the sum of its proper divisors (66602107060).
133204214114 is an equidigital number, since it uses as much as digits as its factorization.
133204214114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66602107059.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 133204214114 its reverse (411412402331), we get a palindrome (544616616445).
The spelling of 133204214114 in words is "one hundred thirty-three billion, two hundred four million, two hundred fourteen thousand, one hundred fourteen".
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