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13320434044403 = 41849318297547
BaseRepresentation
bin1100000111010110011110…
…1111010100110111110011
31202011102100221200120020222
43001311213233110313303
53221220222103410103
644155153430123255
72543240526134363
oct301654757246763
952142327616228
1013320434044403
114276189833aa2
1215b170a4b052b
1375815b093055
143409d8d569a3
15181765c4c638
hexc1d67bd4df3

13320434044403 has 4 divisors (see below), whose sum is σ = 13320752383800. Its totient is φ = 13320115705008.

The previous prime is 13320434044367. The next prime is 13320434044439. The reversal of 13320434044403 is 30444043402331.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13320434044367) and next prime (13320434044439).

It is a cyclic number.

It is not a de Polignac number, because 13320434044403 - 218 = 13320433782259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13320434044103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159106925 + ... + 159190622.

It is an arithmetic number, because the mean of its divisors is an integer number (3330188095950).

Almost surely, 213320434044403 is an apocalyptic number.

13320434044403 is a deficient number, since it is larger than the sum of its proper divisors (318339397).

13320434044403 is an equidigital number, since it uses as much as digits as its factorization.

13320434044403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318339396.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 13320434044403 its reverse (30444043402331), we get a palindrome (43764477446734).

The spelling of 13320434044403 in words is "thirteen trillion, three hundred twenty billion, four hundred thirty-four million, forty-four thousand, four hundred three".

Divisors: 1 41849 318297547 13320434044403