13320440132947 has 2 divisors, whose sum is σ = 13320440132948. Its totient is φ = 13320440132946.

The previous prime is 13320440132941. The next prime is 13320440133067. The reversal of 13320440132947 is 74923104402331.

It is a weak prime.

It is an emirp because it is prime and its reverse (74923104402331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13320440132947 is a prime.

It is a super-3 number, since 3×13320440132947³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13320440132941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660220066473 + 6660220066474.

It is an arithmetic number, because the mean of its divisors is an integer number (6660220066474).

Almost surely, 2^{13320440132947} is an apocalyptic number.

13320440132947 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320440132947 is an equidigital number, since it uses as much as digits as its factorization.

13320440132947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 435456, while the sum is 43.

The spelling of 13320440132947 in words is "thirteen trillion, three hundred twenty billion, four hundred forty million, one hundred thirty-two thousand, nine hundred forty-seven".