Base | Representation |
---|---|
bin | 1100000111010110100000… |
… | …0110100011101010110001 |
3 | 1202011102101101010222001111 |
4 | 3001311220012203222301 |
5 | 3221220230133244241 |
6 | 44155154204433321 |
7 | 2543240631660265 |
oct | 301655006435261 |
9 | 52142341128044 |
10 | 13320440134321 |
11 | 4276192213491 |
12 | 15b1710548841 |
13 | 75815c415c58 |
14 | 3409d9aa00a5 |
15 | 181766551c81 |
hex | c1d681a3ab1 |
13320440134321 has 2 divisors, whose sum is σ = 13320440134322. Its totient is φ = 13320440134320.
The previous prime is 13320440134301. The next prime is 13320440134333. The reversal of 13320440134321 is 12343104402331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12266532574321 + 1053907560000 = 3502361^2 + 1026600^2 .
It is a cyclic number.
It is not a de Polignac number, because 13320440134321 - 223 = 13320431745713 is a prime.
It is not a weakly prime, because it can be changed into another prime (13320440134301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660220067160 + 6660220067161.
It is an arithmetic number, because the mean of its divisors is an integer number (6660220067161).
Almost surely, 213320440134321 is an apocalyptic number.
It is an amenable number.
13320440134321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320440134321 is an equidigital number, since it uses as much as digits as its factorization.
13320440134321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13320440134321 its reverse (12343104402331), we get a palindrome (25663544536652).
The spelling of 13320440134321 in words is "thirteen trillion, three hundred twenty billion, four hundred forty million, one hundred thirty-four thousand, three hundred twenty-one".
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