13321000213041 has 4 divisors (see below), whose sum is σ = 17761333617392. Its totient is φ = 8880666808692.

The previous prime is 13321000212983. The next prime is 13321000213117. The reversal of 13321000213041 is 14031200012331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13321000213041 - 2¹⁰ = 13321000212017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13321000212999 and 13321000213017.

It is not an unprimeable number, because it can be changed into a prime (13321000215041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220166702171 + ... + 2220166702176.

It is an arithmetic number, because the mean of its divisors is an integer number (4440333404348).

Almost surely, 2^{13321000213041} is an apocalyptic number.

It is an amenable number.

13321000213041 is a deficient number, since it is larger than the sum of its proper divisors (4440333404351).

13321000213041 is an equidigital number, since it uses as much as digits as its factorization.

13321000213041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4440333404350.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13321000213041 its reverse (14031200012331), we get a palindrome (27352200225372).

The spelling of 13321000213041 in words is "thirteen trillion, three hundred twenty-one billion, two hundred thirteen thousand, forty-one".