Base | Representation |
---|---|
bin | 1100000111011000100110… |
… | …0010001111110001101011 |
3 | 1202011110211110120222101001 |
4 | 3001312021202033301223 |
5 | 3221222402231303003 |
6 | 44155330002535431 |
7 | 2543260552415605 |
oct | 301661142176153 |
9 | 52143743528331 |
10 | 13321001041003 |
11 | 427644a89aa27 |
12 | 15b1848367577 |
13 | 75821b6a48b6 |
14 | 340a5038c175 |
15 | 18179a8eb61d |
hex | c1d8988fc6b |
13321001041003 has 2 divisors, whose sum is σ = 13321001041004. Its totient is φ = 13321001041002.
The previous prime is 13321001040973. The next prime is 13321001041037. The reversal of 13321001041003 is 30014010012331.
13321001041003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13321001041003 - 225 = 13320967486571 is a prime.
It is not a weakly prime, because it can be changed into another prime (13321001041043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660500520501 + 6660500520502.
It is an arithmetic number, because the mean of its divisors is an integer number (6660500520502).
Almost surely, 213321001041003 is an apocalyptic number.
13321001041003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321001041003 is an equidigital number, since it uses as much as digits as its factorization.
13321001041003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13321001041003 its reverse (30014010012331), we get a palindrome (43335011053334).
The spelling of 13321001041003 in words is "thirteen trillion, three hundred twenty-one billion, one million, forty-one thousand, three".
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