Base | Representation |
---|---|
bin | 1100000111011000101011… |
… | …1011000001101011010011 |
3 | 1202011110220002101101000101 |
4 | 3001312022323001223103 |
5 | 3221222424211022232 |
6 | 44155332153433231 |
7 | 2543261254266241 |
oct | 301661273015323 |
9 | 52143802341011 |
10 | 13321024314067 |
11 | 4276461a46368 |
12 | 15b185410b817 |
13 | 758223462a42 |
14 | 340a534c9791 |
15 | 18179c9971e7 |
hex | c1d8aec1ad3 |
13321024314067 has 2 divisors, whose sum is σ = 13321024314068. Its totient is φ = 13321024314066.
The previous prime is 13321024314001. The next prime is 13321024314077. The reversal of 13321024314067 is 76041342012331.
13321024314067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13321024314067 - 235 = 13286664575699 is a prime.
It is not a weakly prime, because it can be changed into another prime (13321024314077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660512157033 + 6660512157034.
It is an arithmetic number, because the mean of its divisors is an integer number (6660512157034).
Almost surely, 213321024314067 is an apocalyptic number.
13321024314067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321024314067 is an equidigital number, since it uses as much as digits as its factorization.
13321024314067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 37.
Adding to 13321024314067 its reverse (76041342012331), we get a palindrome (89362366326398).
The spelling of 13321024314067 in words is "thirteen trillion, three hundred twenty-one billion, twenty-four million, three hundred fourteen thousand, sixty-seven".
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