Base | Representation |
---|---|
bin | 10011011000100111100… |
… | …010111100010100000001 |
3 | 11201100101120102202012222 |
4 | 103120213202330110001 |
5 | 133311121423124441 |
6 | 2455543153300425 |
7 | 165145522335641 |
oct | 23304742742401 |
9 | 4640346382188 |
10 | 1332103333121 |
11 | 473a3a670560 |
12 | 196206864715 |
13 | 98803176542 |
14 | 4868d0aa521 |
15 | 249b7523d4b |
hex | 136278bc501 |
1332103333121 has 32 divisors (see below), whose sum is σ = 1470935531520. Its totient is φ = 1196320406400.
The previous prime is 1332103333087. The next prime is 1332103333151. The reversal of 1332103333121 is 1213333012331.
It is a cyclic number.
It is not a de Polignac number, because 1332103333121 - 214 = 1332103316737 is a prime.
It is a super-2 number, since 2×13321033331212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1332103333151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 353434925 + ... + 353438693.
It is an arithmetic number, because the mean of its divisors is an integer number (45966735360).
Almost surely, 21332103333121 is an apocalyptic number.
1332103333121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1332103333121 is a deficient number, since it is larger than the sum of its proper divisors (138832198399).
1332103333121 is a wasteful number, since it uses less digits than its factorization.
1332103333121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4925.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 1332103333121 its reverse (1213333012331), we get a palindrome (2545436345452).
The spelling of 1332103333121 in words is "one trillion, three hundred thirty-two billion, one hundred three million, three hundred thirty-three thousand, one hundred twenty-one".
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