Base | Representation |
---|---|
bin | 10011011000101000101… |
… | …100010000001100111011 |
3 | 11201100102220121010022221 |
4 | 103120220230100030323 |
5 | 133311141333113344 |
6 | 2455545121224511 |
7 | 165146144600014 |
oct | 23305054201473 |
9 | 4640386533287 |
10 | 1332122551099 |
11 | 473a4a4a728a |
12 | 196211192137 |
13 | 98807144a22 |
14 | 4869187000b |
15 | 249b906d184 |
hex | 13628b1033b |
1332122551099 has 2 divisors, whose sum is σ = 1332122551100. Its totient is φ = 1332122551098.
The previous prime is 1332122550989. The next prime is 1332122551117. The reversal of 1332122551099 is 9901552212331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332122551099 - 219 = 1332122026811 is a prime.
It is a super-2 number, since 2×13321225510992 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1332122557099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666061275549 + 666061275550.
It is an arithmetic number, because the mean of its divisors is an integer number (666061275550).
Almost surely, 21332122551099 is an apocalyptic number.
1332122551099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332122551099 is an equidigital number, since it uses as much as digits as its factorization.
1332122551099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145800, while the sum is 43.
The spelling of 1332122551099 in words is "one trillion, three hundred thirty-two billion, one hundred twenty-two million, five hundred fifty-one thousand, ninety-nine".
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