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133212331010081 is a prime number
BaseRepresentation
bin11110010010011111101001…
…101010110110100000100001
3122110122222022101112110112102
4132102133221222312200201
5114430022323214310311
61151152522223540145
740026162513602351
oct3622375152664041
9573588271473472
10133212331010081
113949a03a020524
1212b3553815a655
135943b3b00350b
1424c7722b1ab61
151060259ab943b
hex7927e9ab6821

133212331010081 has 2 divisors, whose sum is σ = 133212331010082. Its totient is φ = 133212331010080.

The previous prime is 133212331010053. The next prime is 133212331010107. The reversal of 133212331010081 is 180010133212331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122785347531025 + 10426983479056 = 11080855^2 + 3229084^2 .

It is a cyclic number.

It is not a de Polignac number, because 133212331010081 - 214 = 133212330993697 is a prime.

It is a super-2 number, since 2×1332123310100812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133212331010041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66606165505040 + 66606165505041.

It is an arithmetic number, because the mean of its divisors is an integer number (66606165505041).

Almost surely, 2133212331010081 is an apocalyptic number.

It is an amenable number.

133212331010081 is a deficient number, since it is larger than the sum of its proper divisors (1).

133212331010081 is an equidigital number, since it uses as much as digits as its factorization.

133212331010081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 133212331010081 in words is "one hundred thirty-three trillion, two hundred twelve billion, three hundred thirty-one million, ten thousand, eighty-one".