Search a number
-
+
13321242120034 = 228403234504139
BaseRepresentation
bin1100000111011001011111…
…1001111000111101100010
31202011111110021020001122001
43001312113321320331202
53221223400440320114
644155405534034214
72543266540514122
oct301662771707542
952144407201561
1013321242120034
1142765639901a2
1215b18b504896a
13758259612904
14340a743c4c82
151817b1b6c374
hexc1d97e78f62

13321242120034 has 8 divisors (see below), whose sum is σ = 19982566777680. Its totient is φ = 6660386527476.

The previous prime is 13321242119993. The next prime is 13321242120041. The reversal of 13321242120034 is 43002124212331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×133212421200342 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13321242119984 and 13321242120011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117195264 + ... + 117308875.

It is an arithmetic number, because the mean of its divisors is an integer number (2497820847210).

Almost surely, 213321242120034 is an apocalyptic number.

13321242120034 is a deficient number, since it is larger than the sum of its proper divisors (6661324657646).

13321242120034 is a wasteful number, since it uses less digits than its factorization.

13321242120034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234532544.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 13321242120034 its reverse (43002124212331), we get a palindrome (56323366332365).

The spelling of 13321242120034 in words is "thirteen trillion, three hundred twenty-one billion, two hundred forty-two million, one hundred twenty thousand, thirty-four".

Divisors: 1 2 28403 56806 234504139 469008278 6660621060017 13321242120034