Base | Representation |
---|---|
bin | 11110010010100000011111… |
… | …011011101101110110010001 |
3 | 122110200001122020210220201002 |
4 | 132102200133123231312101 |
5 | 114430031200122341423 |
6 | 1151153151524551345 |
7 | 40026224045520032 |
oct | 3622403733556621 |
9 | 573601566726632 |
10 | 133213233012113 |
11 | 3949a46219aa51 |
12 | 12b3574a252555 |
13 | 5943c52b4b227 |
14 | 24c77aa838a89 |
15 | 10602add8e228 |
hex | 79281f6edd91 |
133213233012113 has 2 divisors, whose sum is σ = 133213233012114. Its totient is φ = 133213233012112.
The previous prime is 133213233011983. The next prime is 133213233012121. The reversal of 133213233012113 is 311210332312331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131788723925329 + 1424509086784 = 11479927^2 + 1193528^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133213233012113 is a prime.
It is not a weakly prime, because it can be changed into another prime (133213233012173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66606616506056 + 66606616506057.
It is an arithmetic number, because the mean of its divisors is an integer number (66606616506057).
Almost surely, 2133213233012113 is an apocalyptic number.
It is an amenable number.
133213233012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
133213233012113 is an equidigital number, since it uses as much as digits as its factorization.
133213233012113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 133213233012113 its reverse (311210332312331), we get a palindrome (444423565324444).
The spelling of 133213233012113 in words is "one hundred thirty-three trillion, two hundred thirteen billion, two hundred thirty-three million, twelve thousand, one hundred thirteen".
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