Base | Representation |
---|---|
bin | 111110000010000100… |
… | …0011100111111111001 |
3 | 110201211212100100121012 |
4 | 1330010020130333321 |
5 | 4140310101422334 |
6 | 141110343323305 |
7 | 12424102313624 |
oct | 1740410347771 |
9 | 421755310535 |
10 | 133213310969 |
11 | 5154a494232 |
12 | 21998a50535 |
13 | c73c823c7b |
14 | 663a15adbb |
15 | 36e9ee09ce |
hex | 1f0421cff9 |
133213310969 has 2 divisors, whose sum is σ = 133213310970. Its totient is φ = 133213310968.
The previous prime is 133213310953. The next prime is 133213311013. The reversal of 133213310969 is 969013312331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125659615225 + 7553695744 = 354485^2 + 86912^2 .
It is a cyclic number.
It is not a de Polignac number, because 133213310969 - 24 = 133213310953 is a prime.
It is a super-2 number, since 2×1332133109692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133213316969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66606655484 + 66606655485.
It is an arithmetic number, because the mean of its divisors is an integer number (66606655485).
Almost surely, 2133213310969 is an apocalyptic number.
It is an amenable number.
133213310969 is a deficient number, since it is larger than the sum of its proper divisors (1).
133213310969 is an equidigital number, since it uses as much as digits as its factorization.
133213310969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 78732, while the sum is 41.
The spelling of 133213310969 in words is "one hundred thirty-three billion, two hundred thirteen million, three hundred ten thousand, nine hundred sixty-nine".
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