Search a number
-
+
13322001131002 = 26661000565501
BaseRepresentation
bin1100000111011100010100…
…1001010010010111111010
31202011120102011102210221101
43001313011021102113322
53221231424242143002
644200013130202014
72543324415143104
oct301670511222772
952146364383841
1013322001131002
114276913375393
1215b1a8728330a
1375834a943a25
14340b07120574
151818085e9587
hexc1dc52525fa

13322001131002 has 4 divisors (see below), whose sum is σ = 19983001696506. Its totient is φ = 6661000565500.

The previous prime is 13322001130819. The next prime is 13322001131077. The reversal of 13322001131002 is 20013110022331.

13322001131002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12749677107561 + 572324023441 = 3570669^2 + 756521^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330500282749 + ... + 3330500282752.

Almost surely, 213322001131002 is an apocalyptic number.

13322001131002 is a deficient number, since it is larger than the sum of its proper divisors (6661000565504).

13322001131002 is an equidigital number, since it uses as much as digits as its factorization.

13322001131002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6661000565503.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13322001131002 its reverse (20013110022331), we get a palindrome (33335111153333).

The spelling of 13322001131002 in words is "thirteen trillion, three hundred twenty-two billion, one million, one hundred thirty-one thousand, two".

Divisors: 1 2 6661000565501 13322001131002