Search a number
-
+
13322004030242 = 26661002015121
BaseRepresentation
bin1100000111011100010101…
…0100010110001100100010
31202011120102100220002221122
43001313011110112030202
53221231431012431432
644200013312252242
72543324451606515
oct301670524261442
952146370802848
1013322004030242
114276914a75656
1215b1a88241082
1375834b41a55b
14340b07676d7c
151818089bd612
hexc1dc5516322

13322004030242 has 4 divisors (see below), whose sum is σ = 19983006045366. Its totient is φ = 6661002015120.

The previous prime is 13322004030227. The next prime is 13322004030263. The reversal of 13322004030242 is 24203040022331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9215832706081 + 4106171324161 = 3035759^2 + 2026369^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3330501007559 + ... + 3330501007562.

Almost surely, 213322004030242 is an apocalyptic number.

13322004030242 is a deficient number, since it is larger than the sum of its proper divisors (6661002015124).

13322004030242 is an equidigital number, since it uses as much as digits as its factorization.

13322004030242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6661002015123.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 13322004030242 its reverse (24203040022331), we get a palindrome (37525044052573).

The spelling of 13322004030242 in words is "thirteen trillion, three hundred twenty-two billion, four million, thirty thousand, two hundred forty-two".

Divisors: 1 2 6661002015121 13322004030242