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13322022234113 is a prime number
BaseRepresentation
bin1100000111011100011001…
…1001110010100000000001
31202011120110122010221222002
43001313012121302200001
53221232000142442423
644200015202353345
72543325062415155
oct301670631624001
952146418127862
1013322022234113
11427692427947a
1215b1a9235b855
13758352122288
14340b09c55065
1518180a3b7228
hexc1dc6672801

13322022234113 has 2 divisors, whose sum is σ = 13322022234114. Its totient is φ = 13322022234112.

The previous prime is 13322022234067. The next prime is 13322022234163. The reversal of 13322022234113 is 31143222022331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12243616831744 + 1078405402369 = 3499088^2 + 1038463^2 .

It is a cyclic number.

It is not a de Polignac number, because 13322022234113 - 220 = 13322021185537 is a prime.

It is a super-2 number, since 2×133220222341132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13322022234163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661011117056 + 6661011117057.

It is an arithmetic number, because the mean of its divisors is an integer number (6661011117057).

Almost surely, 213322022234113 is an apocalyptic number.

It is an amenable number.

13322022234113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322022234113 is an equidigital number, since it uses as much as digits as its factorization.

13322022234113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13322022234113 its reverse (31143222022331), we get a palindrome (44465244256444).

The spelling of 13322022234113 in words is "thirteen trillion, three hundred twenty-two billion, twenty-two million, two hundred thirty-four thousand, one hundred thirteen".