Base | Representation |
---|---|
bin | 10011011000101101110… |
… | …010101111101001000011 |
3 | 11201100122212122102121111 |
4 | 103120231302233221003 |
5 | 133311330240420234 |
6 | 2500001415504151 |
7 | 165151234224625 |
oct | 23305562575103 |
9 | 4640585572544 |
10 | 1332208138819 |
11 | 473a93844638 |
12 | 196235988057 |
13 | 9881bab054c |
14 | 4869cd8cc15 |
15 | 249c1827664 |
hex | 1362dcafa43 |
1332208138819 has 2 divisors, whose sum is σ = 1332208138820. Its totient is φ = 1332208138818.
The previous prime is 1332208138777. The next prime is 1332208138837. The reversal of 1332208138819 is 9188318022331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1332208138819 - 29 = 1332208138307 is a prime.
It is a super-2 number, since 2×13322081388192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1332208138889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666104069409 + 666104069410.
It is an arithmetic number, because the mean of its divisors is an integer number (666104069410).
Almost surely, 21332208138819 is an apocalyptic number.
1332208138819 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332208138819 is an equidigital number, since it uses as much as digits as its factorization.
1332208138819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 49.
The spelling of 1332208138819 in words is "one trillion, three hundred thirty-two billion, two hundred eight million, one hundred thirty-eight thousand, eight hundred nineteen".
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