13322212403113 has 2 divisors, whose sum is σ = 13322212403114. Its totient is φ = 13322212403112.

The previous prime is 13322212403099. The next prime is 13322212403117. The reversal of 13322212403113 is 31130421222331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7924382640784 + 5397829762329 = 2815028^2 + 2323323^2 .

It is an emirp because it is prime and its reverse (31130421222331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13322212403113 - 2¹³ = 13322212394921 is a prime.

It is a super-3 number, since 3×13322212403113³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13322212403117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661106201556 + 6661106201557.

It is an arithmetic number, because the mean of its divisors is an integer number (6661106201557).

Almost surely, 2^{13322212403113} is an apocalyptic number.

It is an amenable number.

13322212403113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322212403113 is an equidigital number, since it uses as much as digits as its factorization.

13322212403113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13322212403113 its reverse (31130421222331), we get a palindrome (44452633625444).

The spelling of 13322212403113 in words is "thirteen trillion, three hundred twenty-two billion, two hundred twelve million, four hundred three thousand, one hundred thirteen".