Base | Representation |
---|---|
bin | 11110010010101001101101… |
… | …011001111110011010011011 |
3 | 122110201000012001211112200111 |
4 | 132102221231121332122123 |
5 | 114430211433031104430 |
6 | 1151201510031345151 |
7 | 40030024245140251 |
oct | 3622515531763233 |
9 | 573630161745614 |
10 | 133223131113115 |
11 | 394a368143680a |
12 | 12b376510821b7 |
13 | 5944b6c6ab724 |
14 | 24c80692345d1 |
15 | 106068cd1ec2a |
hex | 792a6d67e69b |
133223131113115 has 16 divisors (see below), whose sum is σ = 161471861381376. Its totient is φ = 105514383196800.
The previous prime is 133223131113113. The next prime is 133223131113173. The reversal of 133223131113115 is 511311131322331.
It is not a de Polignac number, because 133223131113115 - 21 = 133223131113113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133223131113113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329860696 + ... + 330264325.
It is an arithmetic number, because the mean of its divisors is an integer number (10091991336336).
Almost surely, 2133223131113115 is an apocalyptic number.
133223131113115 is a deficient number, since it is larger than the sum of its proper divisors (28248730268261).
133223131113115 is a wasteful number, since it uses less digits than its factorization.
133223131113115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 660125430.
The product of its digits is 4860, while the sum is 31.
Adding to 133223131113115 its reverse (511311131322331), we get a palindrome (644534262435446).
The spelling of 133223131113115 in words is "one hundred thirty-three trillion, two hundred twenty-three billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred fifteen".
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