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133224040132 = 2233306010033
BaseRepresentation
bin111110000010011000…
…1011000011011000100
3110201212121112110020121
41330010301120123010
54140320323241012
6141111405311324
712424262441161
oct1740461303304
9421777473217
10133224040132
1151555552207
12219a0565544
13c741b0c6a1
14663b751068
1536eae0ea07
hex1f04c586c4

133224040132 has 6 divisors (see below), whose sum is σ = 233142070238. Its totient is φ = 66612020064.

The previous prime is 133224040099. The next prime is 133224040139. The reversal of 133224040132 is 231040422331.

It can be written as a sum of positive squares in only one way, i.e., 131285927556 + 1938112576 = 362334^2 + 44024^2 .

It is a junction number, because it is equal to n+sod(n) for n = 133224040097 and 133224040106.

It is not an unprimeable number, because it can be changed into a prime (133224040139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16653005013 + ... + 16653005020.

Almost surely, 2133224040132 is an apocalyptic number.

It is an amenable number.

133224040132 is a deficient number, since it is larger than the sum of its proper divisors (99918030106).

133224040132 is a wasteful number, since it uses less digits than its factorization.

133224040132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33306010037 (or 33306010035 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 133224040132 its reverse (231040422331), we get a palindrome (364264462463).

The spelling of 133224040132 in words is "one hundred thirty-three billion, two hundred twenty-four million, forty thousand, one hundred thirty-two".

Divisors: 1 2 4 33306010033 66612020066 133224040132