Base | Representation |
---|---|
bin | 11000110100001001… |
… | …11110010101111001 |
3 | 1021101110110201112202 |
4 | 30122010332111321 |
5 | 204241014212213 |
6 | 10041545315545 |
7 | 651066434330 |
oct | 143204762571 |
9 | 37343421482 |
10 | 13322413433 |
11 | 571717843a |
12 | 26b9795bb5 |
13 | 1344119594 |
14 | 9054d4d17 |
15 | 52e8dbb58 |
hex | 31a13e579 |
13322413433 has 8 divisors (see below), whose sum is σ = 15596972160. Its totient is φ = 11140693920.
The previous prime is 13322413421. The next prime is 13322413453. The reversal of 13322413433 is 33431422331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13322413433 - 24 = 13322413417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13322413396 and 13322413405.
It is not an unprimeable number, because it can be changed into a prime (13322413453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23209493 + ... + 23210066.
It is an arithmetic number, because the mean of its divisors is an integer number (1949621520).
Almost surely, 213322413433 is an apocalyptic number.
It is an amenable number.
13322413433 is a deficient number, since it is larger than the sum of its proper divisors (2274558727).
13322413433 is an equidigital number, since it uses as much as digits as its factorization.
13322413433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46419607.
The product of its digits is 15552, while the sum is 29.
Adding to 13322413433 its reverse (33431422331), we get a palindrome (46753835764).
The spelling of 13322413433 in words is "thirteen billion, three hundred twenty-two million, four hundred thirteen thousand, four hundred thirty-three".
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