Base | Representation |
---|---|
bin | 10011011000110000011… |
… | …111110100101001100001 |
3 | 11201100210001000112111112 |
4 | 103120300133310221201 |
5 | 133311423344311431 |
6 | 2500010120153105 |
7 | 165152324664053 |
oct | 23306037645141 |
9 | 4640701015445 |
10 | 1332253510241 |
11 | 474007413885 |
12 | 196249008795 |
13 | 98828307c44 |
14 | 486a4ddd8d3 |
15 | 249c57dac2b |
hex | 136307f4a61 |
1332253510241 has 2 divisors, whose sum is σ = 1332253510242. Its totient is φ = 1332253510240.
The previous prime is 1332253510223. The next prime is 1332253510267. The reversal of 1332253510241 is 1420153522331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1081974432400 + 250279077841 = 1040180^2 + 500279^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332253510241 - 218 = 1332253248097 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1332253510198 and 1332253510207.
It is not a weakly prime, because it can be changed into another prime (1332253510271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666126755120 + 666126755121.
It is an arithmetic number, because the mean of its divisors is an integer number (666126755121).
Almost surely, 21332253510241 is an apocalyptic number.
It is an amenable number.
1332253510241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332253510241 is an equidigital number, since it uses as much as digits as its factorization.
1332253510241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
The spelling of 1332253510241 in words is "one trillion, three hundred thirty-two billion, two hundred fifty-three million, five hundred ten thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •