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1332303111241 is a prime number
BaseRepresentation
bin10011011000110011011…
…101000010010001001001
311201100220111100112021121
4103120303131002101021
5133312024044024431
62500015051235241
7165153466410304
oct23306335022111
94640814315247
101332303111241
11474032411843
12196261748b21
139883568384b
14486ab831b3b
15249c9d37611
hex13633742449

1332303111241 has 2 divisors, whose sum is σ = 1332303111242. Its totient is φ = 1332303111240.

The previous prime is 1332303111193. The next prime is 1332303111379. The reversal of 1332303111241 is 1421113032331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1329397470025 + 2905641216 = 1152995^2 + 53904^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332303111241 - 233 = 1323713176649 is a prime.

It is not a weakly prime, because it can be changed into another prime (1332307111241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666151555620 + 666151555621.

It is an arithmetic number, because the mean of its divisors is an integer number (666151555621).

Almost surely, 21332303111241 is an apocalyptic number.

It is an amenable number.

1332303111241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332303111241 is an equidigital number, since it uses as much as digits as its factorization.

1332303111241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1332303111241 its reverse (1421113032331), we get a palindrome (2753416143572).

The spelling of 1332303111241 in words is "one trillion, three hundred thirty-two billion, three hundred three million, one hundred eleven thousand, two hundred forty-one".