13323114014233 has 4 divisors (see below), whose sum is σ = 13373772242688. Its totient is φ = 13272455785780.

The previous prime is 13323114014201. The next prime is 13323114014257. The reversal of 13323114014233 is 33241041132331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13323114014233 - 2⁵ = 13323114014201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13323114014195 and 13323114014204.

It is not an unprimeable number, because it can be changed into a prime (13383114014233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25329113833 + ... + 25329114358.

It is an arithmetic number, because the mean of its divisors is an integer number (3343443060672).

Almost surely, 2^{13323114014233} is an apocalyptic number.

It is an amenable number.

13323114014233 is a deficient number, since it is larger than the sum of its proper divisors (50658228455).

13323114014233 is an equidigital number, since it uses as much as digits as its factorization.

13323114014233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50658228454.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13323114014233 its reverse (33241041132331), we get a palindrome (46564155146564).

The spelling of 13323114014233 in words is "thirteen trillion, three hundred twenty-three billion, one hundred fourteen million, fourteen thousand, two hundred thirty-three".