Base | Representation |
---|---|
bin | 11110010010110001010101… |
… | …000010000101100010011001 |
3 | 122110201210022012212101011011 |
4 | 132102301111002011202121 |
5 | 114430330211401212444 |
6 | 1151205341515133521 |
7 | 40030434054512062 |
oct | 3622612502054231 |
9 | 573653265771134 |
10 | 133231312132249 |
11 | 394a709a402551 |
12 | 12b39154a442a1 |
13 | 5945874591556 |
14 | 24c860397d569 |
15 | 10609bb175734 |
hex | 792c55085899 |
133231312132249 has 2 divisors, whose sum is σ = 133231312132250. Its totient is φ = 133231312132248.
The previous prime is 133231312132229. The next prime is 133231312132267. The reversal of 133231312132249 is 942231213132331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132835882448025 + 395429684224 = 11525445^2 + 628832^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133231312132249 is a prime.
It is not a weakly prime, because it can be changed into another prime (133231312132229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66615656066124 + 66615656066125.
It is an arithmetic number, because the mean of its divisors is an integer number (66615656066125).
Almost surely, 2133231312132249 is an apocalyptic number.
It is an amenable number.
133231312132249 is a deficient number, since it is larger than the sum of its proper divisors (1).
133231312132249 is an equidigital number, since it uses as much as digits as its factorization.
133231312132249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 139968, while the sum is 40.
The spelling of 133231312132249 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, three hundred twelve million, one hundred thirty-two thousand, two hundred forty-nine".
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