Base | Representation |
---|---|
bin | 1100000111100000100010… |
… | …0111000001100111101011 |
3 | 1202011200100001020201112201 |
4 | 3001320020213001213223 |
5 | 3221241234022001141 |
6 | 44200321322121031 |
7 | 2543364440651161 |
oct | 301701047014753 |
9 | 52150301221481 |
10 | 13323133000171 |
11 | 4277344277455 |
12 | 15b2142350177 |
13 | 75849b2a23b7 |
14 | 340bb3597231 |
15 | 181872b78031 |
hex | c1e089c19eb |
13323133000171 has 2 divisors, whose sum is σ = 13323133000172. Its totient is φ = 13323133000170.
The previous prime is 13323133000141. The next prime is 13323133000241. The reversal of 13323133000171 is 17100033132331.
It is a weak prime.
It is an emirp because it is prime and its reverse (17100033132331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13323133000171 - 241 = 11124109744619 is a prime.
It is a super-2 number, since 2×133231330001712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13323133000141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661566500085 + 6661566500086.
It is an arithmetic number, because the mean of its divisors is an integer number (6661566500086).
Almost surely, 213323133000171 is an apocalyptic number.
13323133000171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323133000171 is an equidigital number, since it uses as much as digits as its factorization.
13323133000171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 28.
The spelling of 13323133000171 in words is "thirteen trillion, three hundred twenty-three billion, one hundred thirty-three million, one hundred seventy-one", and thus it is an aban number.
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