13323310011001 has 4 divisors (see below), whose sum is σ = 13405048109392. Its totient is φ = 13241571912612.

The previous prime is 13323310010999. The next prime is 13323310011019. The reversal of 13323310011001 is 10011001332331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13323310011001 - 2¹ = 13323310010999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13323310011001.

It is not an unprimeable number, because it can be changed into a prime (13323310011041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40869048951 + ... + 40869049276.

It is an arithmetic number, because the mean of its divisors is an integer number (3351262027348).

Almost surely, 2^{13323310011001} is an apocalyptic number.

It is an amenable number.

13323310011001 is a deficient number, since it is larger than the sum of its proper divisors (81738098391).

13323310011001 is an equidigital number, since it uses as much as digits as its factorization.

13323310011001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81738098390.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13323310011001 its reverse (10011001332331), we get a palindrome (23334311343332).

The spelling of 13323310011001 in words is "thirteen trillion, three hundred twenty-three billion, three hundred ten million, eleven thousand, one".