Base | Representation |
---|---|
bin | 10011011000110101001… |
… | …000010001100101101001 |
3 | 11201100222110020202220201 |
4 | 103120311020101211221 |
5 | 133312103243122101 |
6 | 2500021533552201 |
7 | 165154260354043 |
oct | 23306510214551 |
9 | 4640873222821 |
10 | 1332331223401 |
11 | 474047272932 |
12 | 19626b045661 |
13 | 9883b447469 |
14 | 486b146ca93 |
15 | 249cc53be01 |
hex | 13635211969 |
1332331223401 has 2 divisors, whose sum is σ = 1332331223402. Its totient is φ = 1332331223400.
The previous prime is 1332331223393. The next prime is 1332331223471. The reversal of 1332331223401 is 1043221332331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1207633957776 + 124697265625 = 1098924^2 + 353125^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332331223401 - 23 = 1332331223393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1332331223401.
It is not a weakly prime, because it can be changed into another prime (1332331223471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666165611700 + 666165611701.
It is an arithmetic number, because the mean of its divisors is an integer number (666165611701).
Almost surely, 21332331223401 is an apocalyptic number.
It is an amenable number.
1332331223401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332331223401 is an equidigital number, since it uses as much as digits as its factorization.
1332331223401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 1332331223401 its reverse (1043221332331), we get a palindrome (2375552555732).
The spelling of 1332331223401 in words is "one trillion, three hundred thirty-two billion, three hundred thirty-one million, two hundred twenty-three thousand, four hundred one".
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