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13324044220134 = 239532330193113
BaseRepresentation
bin1100000111100011111011…
…1011000011011011100110
31202011202200112212111100020
43001320332323003123212
53221300120310021014
644200551552500010
72543426144130144
oct301707673033346
952152615774306
1013324044220134
1142777716724aa
1215b235754a606
137585b4cc69cb
14340c5c5d4594
151818c7b6e1a9
hexc1e3eec36e6

13324044220134 has 16 divisors (see below), whose sum is σ = 26676050769072. Its totient is φ = 4436687685248.

The previous prime is 13324044220093. The next prime is 13324044220141. The reversal of 13324044220134 is 43102244042331.

It is a junction number, because it is equal to n+sod(n) for n = 13324044220095 and 13324044220104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1165090839 + ... + 1165102274.

It is an arithmetic number, because the mean of its divisors is an integer number (1667253173067).

Almost surely, 213324044220134 is an apocalyptic number.

13324044220134 is an abundant number, since it is smaller than the sum of its proper divisors (13352006548938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13324044220134 is a wasteful number, since it uses less digits than its factorization.

13324044220134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2330194071.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 13324044220134 its reverse (43102244042331), we get a palindrome (56426288262465).

The spelling of 13324044220134 in words is "thirteen trillion, three hundred twenty-four billion, forty-four million, two hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 3 6 953 1906 2859 5718 2330193113 4660386226 6990579339 13981158678 2220674036689 4441348073378 6662022110067 13324044220134