Base | Representation |
---|---|
bin | 11110010010111010101000… |
… | …100011011111000110101010 |
3 | 122110202202002112001212120022 |
4 | 132102322220203133012222 |
5 | 114431011142123044432 |
6 | 1151214113145200442 |
7 | 40031236464350111 |
oct | 3622725043370652 |
9 | 573682075055508 |
10 | 133241303331242 |
11 | 395003571561a7 |
12 | 12b3b082a90122 |
13 | 59467a74b9b12 |
14 | 24c8cb0890c78 |
15 | 1060da3395b12 |
hex | 792ea88df1aa |
133241303331242 has 4 divisors (see below), whose sum is σ = 199861954996866. Its totient is φ = 66620651665620.
The previous prime is 133241303331223. The next prime is 133241303331259. The reversal of 133241303331242 is 242133303142331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 96666277273801 + 36575026057441 = 9831901^2 + 6047729^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33310325832809 + ... + 33310325832812.
Almost surely, 2133241303331242 is an apocalyptic number.
133241303331242 is a deficient number, since it is larger than the sum of its proper divisors (66620651665624).
133241303331242 is an equidigital number, since it uses as much as digits as its factorization.
133241303331242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66620651665623.
The product of its (nonzero) digits is 93312, while the sum is 35.
Adding to 133241303331242 its reverse (242133303142331), we get a palindrome (375374606473573).
The spelling of 133241303331242 in words is "one hundred thirty-three trillion, two hundred forty-one billion, three hundred three million, three hundred thirty-one thousand, two hundred forty-two".
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