Base | Representation |
---|---|
bin | 11000110100010111… |
… | …10011000010011001 |
3 | 1021101120211121012001 |
4 | 30122023303002121 |
5 | 204241443432022 |
6 | 10042051521001 |
7 | 651120564241 |
oct | 143213630231 |
9 | 37346747161 |
10 | 13324202137 |
11 | 571818a304 |
12 | 26ba2b9161 |
13 | 13445c479c |
14 | 90583cb21 |
15 | 52eb41b27 |
hex | 31a2f3099 |
13324202137 has 2 divisors, whose sum is σ = 13324202138. Its totient is φ = 13324202136.
The previous prime is 13324202131. The next prime is 13324202153. The reversal of 13324202137 is 73120242331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8476700761 + 4847501376 = 92069^2 + 69624^2 .
It is an emirp because it is prime and its reverse (73120242331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13324202137 - 211 = 13324200089 is a prime.
It is not a weakly prime, because it can be changed into another prime (13324202131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662101068 + 6662101069.
It is an arithmetic number, because the mean of its divisors is an integer number (6662101069).
Almost surely, 213324202137 is an apocalyptic number.
It is an amenable number.
13324202137 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324202137 is an equidigital number, since it uses as much as digits as its factorization.
13324202137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 13324202137 its reverse (73120242331), we get a palindrome (86444444468).
The spelling of 13324202137 in words is "thirteen billion, three hundred twenty-four million, two hundred two thousand, one hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •