Base | Representation |
---|---|
bin | 111110000010111110… |
… | …1111010100110000010 |
3 | 110201221000021202101100 |
4 | 1330011331322212002 |
5 | 4140340442244132 |
6 | 141113403315230 |
7 | 12424625121501 |
oct | 1740575724602 |
9 | 421830252340 |
10 | 133244103042 |
11 | 51565905826 |
12 | 219a721bb16 |
13 | c74601562b |
14 | 6640294838 |
15 | 36eca7437c |
hex | 1f05f7a982 |
133244103042 has 12 divisors (see below), whose sum is σ = 288695556630. Its totient is φ = 44414701008.
The previous prime is 133244103019. The next prime is 133244103071. The reversal of 133244103042 is 240301442331.
It can be written as a sum of positive squares in only one way, i.e., 133050587121 + 193515921 = 364761^2 + 13911^2 .
It is a super-2 number, since 2×1332441030422 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133244102997 and 133244103015.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3701225067 + ... + 3701225102.
Almost surely, 2133244103042 is an apocalyptic number.
133244103042 is an abundant number, since it is smaller than the sum of its proper divisors (155451453588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133244103042 is a wasteful number, since it uses less digits than its factorization.
133244103042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7402450177 (or 7402450174 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 133244103042 its reverse (240301442331), we get a palindrome (373545545373).
The spelling of 133244103042 in words is "one hundred thirty-three billion, two hundred forty-four million, one hundred three thousand, forty-two".
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